Question

Moment of inertia of a sphere about its diameter is 2/5 MR. What is its moment of inertia about an axis
perpendicular to its two diameters and passing through their point of Intersection​

Answer 1

Answer:

it's answer is again 2 by 5 MR SQUARe

because the given axis in the question is also diameter of the sphere....

Hope it helps....

thanks

Answer 2

The moment of inertia about an axis  perpendicular to its two diameters and passing through their point of intersection​ is $\dfrac{7}{5}MR^2$

Explanation:

It is given that,

Moment of inertia of a sphere about its diameter is $\dfrac{2}{5}MR^2$

Let I is the moment of inertia about an axis  perpendicular to its two diameters and passing through their point of Intersection​. It can be calculated using the theorem of parallel axis,

$I=\dfrac{2}{5}MR^2+MR^2$

$I=\dfrac{7}{5}MR^2$

Hence, this is the required solution.

Learn more,

Theorem of parallel axis

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