moment of inertia of a square lamina about its centre of mass
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While finding Moment of Inertia remember a trick,
“Moment of Inertia doesn't changes if the mass, distance from the concerned axis and the distribution of mass about that axis is not changed.”
Thus, lets imagine we have a particle of mass of m situated about an axis in r distance. Thus, its moment of inertia about that axis will be mr^2.
Now, suppose we have a ring of same mass. Now, as I said that here the mass remains constant. the position of axis is not changed and also the distribution is also unchanged(uniformly distributed about the axis and all the mass is situated at the same distance about the axis), thus its moment of inertia will also be mr^2.
shreyas114341:
but what will be that for the square lamina passing through the centre of mass
Moment of Inertia of the square plate about the axis passing through the center and perpendicular to it will be, I(z)= (ma^2)/6
how can we prove this??
by using perpendicular axis theorem
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