moment of inertia of a thin rod of length r about an axis passing through one end and perpendicular to its length is MR2/3. find the value of radius of gyration for the given scenerio.
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Explanation:
radius of gyration (k) =√moment of inertia (I) /mass(m)
k=√I/m
k=MR²/3M
k=R²/3 .......answer to your problem
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