Physics, asked by vikash2488, 1 year ago

Moment of inertia of a triangular section of base (b) and height (h) about an axis passing through its C.G. and parallel to the base, is
A.bh3/4
B.bh3/8
C. bh3/12
D.bh3/36

Answers

Answered by amritanshu6
7
D. bh3/36 is the correct answer.

PLEASE MARK MY ANSWER AS A BRAINLIEST.
Answered by Anonymous
0

The moment of inertia of a triangular section of base (b) and height (h) about an axis passing through its C.G. and parallel to the base, is bh3/36. (option D)

  • The moment of inertia is defined as the sum of the product of the mass of each and every particle with its square of a distance from its axis of rotation.
  • The S.I unit of moment of inertia is Kg m^2.
  • Moment of inertia is also called angular or rotational inertia as it only acts on a specified axis of symmetry.
  • It depends on axis of rotation as the definition says but it also depends on mass distribution along its axis.
Similar questions