Moment of inertia of a uniform circular disc about a diameter is i. find its moment of inertia about a tangent perpendicular to its plane.
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Answered by
2
ans is 6xi
MI about diameter =mr^2/4=i
4xi= mr^2
MI ABOUT tangent passing perpendicular to it's plan =3mr^2/2=3x4i/2=12i/2=6i
MI about diameter =mr^2/4=i
4xi= mr^2
MI ABOUT tangent passing perpendicular to it's plan =3mr^2/2=3x4i/2=12i/2=6i
Answered by
0
I=14MR2⇒MR2=4I
we have find : I'=32MR2=324I=6I.
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