Question

Moment of inertia of a wheel is 1000 kgm2. At a given instant, its angular velocity is 10 rad/sec. After the wheel rotates through an angle of 100 radians, the angular velocity of the wheel is 100 rad/sec. The torque applied on wheel in nm is

Answer 1

Torque= 4.95 × 10^4 N. m

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And We know that,

ω² - ω1² = 2 ∝ Ф

So therefore,

∝ = ω² - ω1²/2Ф

∝ = (100)² - (10)²/2 * 100

∝ = 49.5 rad/s²

T=I * α  

T = 1000 *  49.5

T = 4.95 × 10^4 N. m