Question

moment of inertia of circular area of diameter about an axis perpendicular to the area and passing through its centre​

Answer 1

Moment of Inertia of ring about an axis

perpendicular to its plane is I=MR squared

By perpendicular axis theorem , moment of

Inertia about any diameter =

$\frac{l}{2} = \: \frac{ {mr}^{2} }{2}$

Moment of Inertia about any tangent is=

$\frac{3l}{2}$

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