Question

moment of inertia of combination of ring and disc of same mass M and radius R kept in contact about the tangent passing through point of contact and in place of both Ring and disc as shows is
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Answer 1

Answer:

if friction force will more then centrifugal force then disc will not move and it will considered as inertial frame

Answer 2

Answer:

7MR^2/2.

Explanation:

The moment of inertia of a disk of mass M and radius of R will be MR^2/2 and to find the moment of inertia of the disk at the tangential position we have to put the parallel axis theorem. So, the moment of inertia at the tangent position of the disk will be MR^2/2 + MR^2 which on solving we will get 3MR^2/2.

The moment of inertial of the ring through the center is MR^2 and through the tangent will be MR^2 + MR^2=2MR^2.

So, the total moment when the ring and disk are in combination will be 3MR^2/2 + 2MR^2 which on solving we will get 7MR^2/2.