Moment of inertia of cylinder about perpendicular bisector
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Answer:I=Mr^2/4+Ml^2/12
Where M is mass of cylinder, l is length and r is radius of cylinder
Explanation:
Answered by
0
Answer:
Explanation:
I=(Mr^2/4)+(Ml^2/12)
Where M is mass of cylinder, l is length and r is radius of cylinder
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