Moment of inertia of disc of radius R about a diametric axis is 25kg/m². MI of disc about a parallel axis at a distance R/2 from centre is
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11
Answer:
50
Explanation:
MI about diameter = M(R^2)/4
=25 kg/m^2
MI about ll(L) axis=M(R^2)/4 + M(R^2)/2
= 2*M(R^2)/4
= 2*25 = 50 kg/m^2
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