Math, asked by nitinpunia538, 3 months ago

moment of Inertia of rectangular plate of sides 10,9 and mass 5 about line through center of the
plate and parallel to the side 10
(a) 145
(b) 155
(c) 125
(d) 135​

Answers

Answered by pulakmath007
1

SOLUTION

TO CHOOSE THE CORRECT OPTION

The moment of Inertia of rectangular plate of sides 10,9 and mass 5 about line through center of the plate and parallel to the side 10

(a) 145

(b) 155

(c) 125

(d) 135

FORMULA TO BE IMPLEMENTED

The moment of Inertia of rectangular plate of sides b , l and mass m about line through center of the plate and parallel to the side b is

 =  \displaystyle \sf{ \frac{m {l}^{2} }{3} }

EVALUATION

Here the given sides are 10 , 9 and mass is 5

Hence the moment of Inertia of rectangular plate of sides 10,9 and mass 5 about line through center of the plate and parallel to the side 10 is

 =  \displaystyle \sf{ \frac{5 \times  {9}^{2} }{3} }

 =  \displaystyle \sf{ \frac{5 \times  81 }{3} }

 =  \displaystyle \sf{5  \times 27}

 = 135

FINAL ANSWER

Hence the correct option is

(d) 135

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