Question

moment of inertia of rod of length 2a and mass m passing through its end points is (a) 1/3ma2 (b) 1/3 ma3 (c) 1/5ma2​

Answer 1

Answer:

Given,

Mass of rod =M

Length of Rod =L

Distance of rods edge from center =

2

L

Moment of inertia of rod at center I

c

=

12

1

ML

2

For moment of inertia at edge apply parallel axis theorem. I

e

=I

c

+M(

2

L

)

2

I=

12

1

ML

2

+M(

2

L

)

2

=

3

1

ML

2

moment of inertia at edge is

3

1

ML

2