Question

Moment of inertia of solid cylinder about perpendicular axes

Answer 1

Moment of inertia: Cylinder about perpendicular axis.... This involves an integral from z=0 to z=L. For any given disk at distance z from the x axis, using the parallel axis theorm gives the moment of inertia about the x axis.

Answer 2

Answer:

Explanation:

# Given-

m = 1.7×10-27 kg

r = 4×10^-10 m

# Solution-

Here,

Total mass M = 2m

Radius of rotation R = r/2

Moment of inertia of hydrogen molecule is given by-

M.I. = MR^2

M.I. = (2m)(r/2)^2

M.I. = mr^2/2

M.I. = 1.7×10-27 × (4×10^-10)^2 / 2

M.I. = 1.36×10^-46 kgm^2