Question

moment of Inertia of solid sphere of radius 5 and mass 10 about a diameter
(a) 200
(b) 300
(c) 100
(d) 50​

Answer 1

Answer:

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Step-by-step explanation:

ur answer is there in image

using image

the moment of Inertia of solid sphere of radius 5 and mass 10 about a diameter is

$i \: = \frac{2}{5} m {r}^{2}$

substitute the given values we get

$i \: = \frac{2}{5} \times 10 \times {5}^{2} \\ i \: = 2 \times 2 \times 25 \\ i \: = 100$

option c is the correct answer