Question

momentum of a body is increased by 2 percent find the percentage change in ke​

Answer 1

Answer:

Explanation:

For example take momentum as 50 kgms^-1

If it is increased by 2% then the new momentum would be 50/100 × 102 = 51 Kgms^-1

Use the equation K.E = momentum^2/2 × mass

Take mass as 5kg

K.E before increase in momentum;

K.E = 50^2/2×5

K.E = 250 J

K.E after increase on momentum

K.E = 51^2/2×5 (mass is constant)

K.E = 260.1 J

Percentage increase in K.E is;

((260.1 - 250)/250) × 100

= 4.04 = 4%

Or use the much simpler method;

K.E = (2%)^2 mass is a constant, so it is not stated here

K.E = 4%