Momentum of a body of mass 4KG is 24KGM/S. Find it's velocity.
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Answered by
4
Before the force is applied we know
momentum=mass×velocity=10 kg m/s
Since mass in the above is 5 kg, then velocity = 2 ms−1
We can now work out kinetic energy, KE:
KE=12mv2=12⋅5⋅22=10 J
The force of 0.2 N is now applied in the direction of travel for 10 seconds. Newton's second law can be expressed as "the force applied equals the rate of change of momentum". OR
F=mv−mut=m⋅v−ut
Where v is the final velocity after applying force, and u is the initial velocity ( 2 ms−1 in this case from above)
So
0.2=5⋅(v−2)10
rearranging helps us find v
2=5⋅(v−2)
25=v−2
v=125 ms−1
Hence final kinetic energy, KE, is
KE=12mv2=12⋅5⋅(125)2=14.4 J
So the overall change in KE is
ΔKE=14.4−10=4.4 J
momentum=mass×velocity=10 kg m/s
Since mass in the above is 5 kg, then velocity = 2 ms−1
We can now work out kinetic energy, KE:
KE=12mv2=12⋅5⋅22=10 J
The force of 0.2 N is now applied in the direction of travel for 10 seconds. Newton's second law can be expressed as "the force applied equals the rate of change of momentum". OR
F=mv−mut=m⋅v−ut
Where v is the final velocity after applying force, and u is the initial velocity ( 2 ms−1 in this case from above)
So
0.2=5⋅(v−2)10
rearranging helps us find v
2=5⋅(v−2)
25=v−2
v=125 ms−1
Hence final kinetic energy, KE, is
KE=12mv2=12⋅5⋅(125)2=14.4 J
So the overall change in KE is
ΔKE=14.4−10=4.4 J
mahajankrishnanshu05:
thanks but can u plz. explain the last 3 lines to me again
Answered by
42
Momentum = 24kgm/s
Mass =, 4kg
Momentum, p = mv
24 = 4*v
V = 24÷4
V=6m/s
Mass =, 4kg
Momentum, p = mv
24 = 4*v
V = 24÷4
V=6m/s
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