momentum of a bullet of mass 20 gram fired from a gun is 20 kilogram metre per second then find kinetic energy of this bullet
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p = mv
20 = 2/100 v
v = 2000/2 = 1000m/s
K.E = 1/2mv² = 1/2 × 2/100 × (1000)²
= 2/200 × 1000000
= 5000×2 = 10,000 Joules
20 = 2/100 v
v = 2000/2 = 1000m/s
K.E = 1/2mv² = 1/2 × 2/100 × (1000)²
= 2/200 × 1000000
= 5000×2 = 10,000 Joules
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