Physics, asked by loveen2, 9 months ago

Momentum of a particle increaseb by 50%.By how much percentage kinetic energy of the particle increases​

Answers

Answered by Anonymous
5

Answer:

square / 2 and increased 50% is equal to 1.5 is equal to empty is equal to (1.5 speaker per square is equal to 2.2 v square / 2 is equal to 2.2 v is equal to 5 - 1 1 crores into 100% the error in the a particle is 100% + then what is the error is the measurement of a pentagon

Explanation:

please mark me brainlist

Answered by Anonymous
4

Momentum is related to kinetic energy as,

K = \frac{p^{2} }{2m}

When momentum is increased by 50%, new momentum is p + 50%p = 1.5p

Initial momentum = p

Initial kinetic energy = K

Mass remains constant

K ∝ p²

\frac{K_{1}}{K_{2}} = \frac{p^2}{(1.5p)^2} \\\\K_{2} = 2.25K_{1}\\

Percentage increase in KE,

\frac{K_{2}-K{1}}{K_{1}}* 100\\\\

= (2.25 -1 )K/K *100

=1.25 * 100

= 125%

Similar questions