Question

Momentum of an object increases by 20%. How much kinetic energy be increase or decrease in percentage

Answer 1

Explanation:

p = m × v

p is i creased by 20% for same object,

therefore, v is increased by 20%

p = m × (v × 20/100)

p = m × (0.2 × v)

K.E initial = 1/2 × m × (v)^2

K.E = 1/2 × m × (0.2 × v)^2

K.E final = 1/2 × m × 0.04 ×(v)^2

therefore % increse in kinetic energy,

K.E% = (K.E final/ K.E initial) × 100%

K.E% = 0.04 × 100%

K.E% = 4%

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