Momentum of an object increases by 20%. How much kinetic energy be increase or decrease in percentage
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Explanation:
p = m × v
p is i creased by 20% for same object,
therefore, v is increased by 20%
p = m × (v × 20/100)
p = m × (0.2 × v)
K.E initial = 1/2 × m × (v)^2
K.E = 1/2 × m × (0.2 × v)^2
K.E final = 1/2 × m × 0.04 ×(v)^2
therefore % increse in kinetic energy,
K.E% = (K.E final/ K.E initial) × 100%
K.E% = 0.04 × 100%
K.E% = 4%
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