momentum of an object is 20 kg MS -1 what will be the momentum of - the velocity is reduced to 1/3 of the of its original magnitude but mass remain the same.
Answers
The correct answer to the above question is as follow -
Given: Momentum of an object = 20 kgms⁻¹
Mass remains the same.
Velocity is reduced to 1/3 of the original magnitude.
To find The momentum of the body when the velocity is reduced to 1/3 the of its original magnitude.
Solution:
Let the initial momentum of the body be P₁ and is equal to 20 kgms⁻¹.
The momentum is the product of the mass of the object and the velocity of the object.
P₁ = m×v
20 = mv ( Let this be the equation 2)
Where m is the mass, and v is the velocity.
According to the question, mass remains the same, and the velocity decreases to 1/3rd of the original magnitude.
Therefore, P₂ = m×1/3v (Let this be the equation 2)
Now we divide equation 1 and equation 2, we get,
P₁/P₂ = mv/m×1/3v
20/P₂ = 3
P₂ = 20/3 kgms⁻¹
Therefore, the momentum of the body when the velocity is reduced to 1/3rd of the original magnitude is 6.6 kgms⁻¹.
Momentum -
- the strength or force that something has when it is moving and its magnitude is equal to the scalar product of mass and velocity.