Momentum of two masses m1 and m2 is same. If m1 >m2 and KE represents kinetic energy , then
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Answered by
1
Answer:
KE with m1>=< KE with m2
Explanation:
As m1 is more so velocity should be less than other velocity.
Now if 1/2mv² if we will do then we can get three results as mass and velocity is not given.
Answered by
1
Explanation:
momentum is same therefore
M1 V1 =M2 V2= P (LETS SAY )---------1
M1>M2 HENCE, V1<V2 (TO MAKE 1 TRUE)
1/2(M1 V1^2)=K.E 1 =1/2(M1.V1)V1
KE 1 = 1/2x p x V1
K.E2=1/2(M2.V2)V2
K.E 2= 1/2x p x V2
SINCE V1<V2
(P/2)x V1 < (P/2)x V2
K.E 1 < K.E 2
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