Question

Mometum of an object is incresed by 100%, calculate the percentage change in its kinetic energy?​

Answer 1

Answer:

Explanation:

KE will increase by 300% as depicted in image. If the momentum increases by 100% , then the p increases to 2p. When momentum of a body increases by 100% then its kinetic energy will increase by 300%.

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Answer 2

Answer:

Kinetic energy is increased by 300%

Explanation:

Momentum (p) and Kinetic energy (K) are related as

• K = p²/(2m)

For an object of mass "m"

• K ∝ p²

From above,

K₂/K₁ = (p₂/p₁)²

Subtract 1 from both the sides

K₂/K₁ - 1 = (p₂/p₁)² - 1

(K₂ - K₁)/K₁ = (p₂/p₁)² - 1

∆K/K₁ = (p₂/p₁)² - 1

∆K = K₁ × [(p₂/p₁)² - 1]

Let,

• Initial Kinetic energy = 100%
• Initial momentum = 100%
• Final momentum = 100% + 100% = 200%

Then,

∆K = 100% × [(200%/100%)² - 1]

∆K = 100% × 3

∆K = 300%