Mona is 27 years older than her daughter. After 16years, she will be
19 years more than thrice the present age of Aditi, what is Aditi’s
present age?
Answers
Answer:
The present age of Aditi is 12 years.
Step-by-step explanation:
Let the present age of Mona be x years and her daughter, Aditi be y years.
Mona is 26 years older than her daughter, Aditi.
x = y + 27
After 16 years,
Mona's age = (x + 16) years
According to the question,
x + 16 = 3y + 19
x + 16 = 3y + 19
x = 3y + 19 – 16
x = 3y + 3
y + 27 = 3y + 3
3y – y = 27 – 3
2y = 24
y = 24/2
y = 12
Therefore, the present age of Aditi is 12 years.
Step-by-step explanation:
- ➟ Mona is 27 years older then her daughter.
- ➟ After 16 years she will be 19 years more then thrice the present age of aditi.
- ⟿ What is aditi's present age ?
❖ To find present age of aditi we have to assume a variable for example :
- Let Mona and her daughter age be a
- and aditi age be b
❑ As given in question Mona is 26 years older then her daughter (Aditi) ,Therefore
- ➤ a = b + 27
❒ And also it is given that After 16 years she will be 19 years more then her present age of aditi, Therefore our 1st equation & 2nd equation be
- ➤ Mona age = (a + 16) years
- ➤ Aditi age = (3b + 19) years
- transferring sides
- On subtracting 19 by 16 we get 3
- Now putting value of a ( b+27), we get
- Again transferring sides
- On subtracting 27 - 3 we get 24
- again subtracting 3b - b we get 2b
- Transferring sides
- Dividing 24 by 2 we get 12