Math, asked by shbo2075, 1 month ago

Mona is 27 years older than her daughter. After 16years, she will be
19 years more than thrice the present age of Aditi, what is Aditi’s
present age?

Answers

Answered by snehitha2
12

Answer:

The present age of Aditi is 12 years.

Step-by-step explanation:

Let the present age of Mona be x years and her daughter, Aditi be y years.

Mona is 26 years older than her daughter, Aditi.

x = y + 27

After 16 years,

Mona's age = (x + 16) years

According to the question,

x + 16 = 3y + 19

x + 16 = 3y + 19

x = 3y + 19 – 16

x = 3y + 3

y + 27 = 3y + 3

3y – y = 27 – 3

2y = 24

y = 24/2

y = 12

Therefore, the present age of Aditi is 12 years.

Answered by Yugant1913
158

Step-by-step explanation:

 \blue {\large{\underline{\underline{\textbf{Given information:---}}}}}

  • ➟ Mona is 27 years older then her daughter.
  • ➟ After 16 years she will be 19 years more then thrice the present age of aditi.

\blue {\large{\underline{\underline{\textbf{What we need to calculate:---}}}}}

  • ⟿ What is aditi's present age ?

\purple {\large{\underline{\underline{\textbf{Finding present age of Aditi's:---}}}}}

❖ To find present age of aditi we have to assume a variable for example :

  • Let Mona and her daughter age be a
  • and aditi age be b

\pink {\large{\underline{\underline{\textbf{Forming an equation :---}}}}}

❑ As given in question Mona is 26 years older then her daughter (Aditi) ,Therefore

  • ➤ a = b + 27

❒ And also it is given that After 16 years she will be 19 years more then her present age of aditi, Therefore our 1st equation & 2nd equation be

  • ➤ Mona age = (a + 16) years
  • ➤ Aditi age = (3b + 19) years

 \qquad \red{ \underline{ { \pmb{ \textbf{Solving  equation \: (1) \: and equation( 2) }}}}}

 \\ ➟ \bf \: a + 16 = 3b + 19 \\

  • transferring sides

 \\ ➟ \bf \: a = 3b + 19 - 16 \\

  • On subtracting 19 by 16 we get 3

 \\   \bf \: ➟ \: a= 3b + 3 \\

  • Now putting value of a ( b+27), we get

 \\  \bf \: ➟  \: b + 27 = 3b + 3 \\

  • Again transferring sides

 \\  \bf \: ➟ \: 27 - 3 = 3b - b \\

  • On subtracting 27 - 3 we get 24

  \\ \bf \: ➟ \: 24 = 3b - b \\

  • again subtracting 3b - b we get 2b

 \\  \bf \: ➟ \: 24 = 2b \\

  • Transferring sides

 \\  \bf \: ➟ \: b \:  =  \dfrac{ \cancel{24}}{ \cancel2}  \\

  • Dividing 24 by 2 we get 12

 \\  \pink{ \large ➟ \:  \underline{ \overline{ \boxed{ \frak{b = 12}}}}} \\

 \underline{ \bigstar \textbf {\:Hence present age of  \red{Aditi's is 12 years  }}}

  \qquad\rule{80mm}{0.6mm}

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