Math, asked by priyanshsubba00, 15 days ago

Mona is 29% younget than Neetu .By how much percent is Neetu older than Mona ?​

Answers

Answered by Anonymous
90

Let Neetu's age = 100 years

Then, Mona's age = 100-20 = 80 years

Difference of ages= 100-80 = 20 years

If Mona is 80 years, then Neetu is older than Mona by = 20 years

If Mona is 1 year, then Neetu is older than Mona by

= 20/80 years

If Mona is 100 years, then Neetu is older than

Mona by = 20/80 years

If Mona is 100 years, then Neetu is older than Mona by = 20/80 x 100 years= (20 ×100)/80

= 25%

Answered by roshni542
1

Answer:

 \huge \tt  \underline\red{↪ Solution}

Neetu Age = 100 years

then Mona age= 100-20 = 80 years

differences of age

→ 100-80

= 20years

if Mona 80 years, then Neetu is older then Mona by = 20 years

if Mona is 1 year then Neetu is older

 \tt \: tan \: mona \: by =  \frac{20}{80} years

if Mona is 100 years then Neetu is older than Mona By

 \tt \:  =  \frac{20}{80} \times 100   \: years\\  \tt \:

 \tt \:  =  \frac{20 \times 100}{80}

 =  \tt \: 25\%

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