Mona's Father is twice as old as Mona. After 12 years he will be just twice his daughter's age. Find their present ages.
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Let the age of mona be x
so, father age = y
By the problem
(I) 3x =y (Present)
(II) 2(x+12) = y+12 (After 12 yrs)
so from the above two equation we can get
x=12 and y=36
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