Question

money did he have?
). Anita's mother is four times as old as Anita. Twenty years later, she will be jus
twice as old as Anita will be then. Find the present age of Anita.with explanation ​

Answer 1

Answer:

Let Anita's age be x

mother's age=4x

after 20 years

Anita's age= x+20

mother's age= 4x+20

According to the question

2(x+20)=4x+20

2x+40=4x+20

40-20=4x-2x

20=2x

x=20/2

x=10

: Anita's age= x=10

Anita's age= x=10: Mother's present age = 40 yrs

Answer 2

Answer:-

Let Anita's age be x and her mother's age be y.

Given:

Anita's mother is four times the age of Anita.

⟹ y = 4x -- equation (1)

And,

After 20 years , Anita's mother will be twice the age of Anita.

• Anita's age after 20 years = (x + 20) years

• Anita's mother's age after 20 years = (y + 20) years.

According to the question,

⟹ y + 20 = 2(x + 20)

⟹ y + 20 = 2x + 40

Substitute the value of y from equation (1).

⟹ 4x + 20 - 2x = 40

⟹ 2x = 40 - 20

⟹ 2x = 20

⟹ x = 20/2

⟹ x = 10 years

Substitute the value of x in equation (1).

⟹ y = 4x

⟹ y = 4(10)

⟹ y = 40 years

∴

• Present age of Anita = x = 10 years.

• Present age of Anita's mother = y = 40 years.