Monic cubic polynomial will statisfy p(1)=1 p(3)=17 and p(5)=49 then find the value of p(2)=?
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Step-by-step explanation:
P(x)=ax^3+bx^2+cx+d
put x=1
p(1)=a+b+c+d
1=a+b+c+d
put x=3
p(3)=27a + 9b + 3c + d = 17
p(5)=125a+25b+5c+d=49
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