Math, asked by vvas0467, 2 months ago

monica buys some chocolates at the rate of Rs. 10 per chocolate. She also buys an equal number of candies at the rate of Rs. 5 per candy. She makes a 20% profit on chocolates and 8% profit on candies. At the end of the day, all chocolates and candies are sold out and her profit is Rs. 240. Find the number of chocolates purchased.

Answers

Answered by bhadurydebmalya16422
0

Step-by-step explanation:

Let, the total number of chocolates are x

According to question, the number of chocolates and the number of candies are same

now, the total cost price of chocolates @ Rs.10 per chocolate are ( 10×x) = 10x

In the same way, the total cost price of candies @ Rs.5 per candie are ( 5×x)= 5x

Now, the profit, 20% of 10x is ( 10x × 20/100) = ( 10x × 1/5) = 10x/5

and the profit, 8% of 5x is ( 5x × 8/100) = ( 5x × 2/25) = 10x/25

Now, as per the mention,

10x/5 + 10x/25 = 240

~ ( 50x + 10x) /25 = 240

~ 60x = ( 25×240)

~ x = ( 25×240)/60 = (5×240)/12 = 5×20=100

So, the number of chocolates are 100

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