Question

Monica has a piece of canvas whose area is 551 m². She uses it to make a
conical tent with a base radius of 7 m. Assuming that all the stitching margins and the
wastage incurred while cutting, amounts to approximately 1 m?, find the volume of the
tent that can be made with it.​

Answer 1

$\LARGE{ \underline{ \orange{ \sf{Required \: answer:}}}}$

Area =451m

radius = 7m

wastage = 1m^2

Formula used :

Area of cone = 1/2×base × height

Volume of cone = 1/3 πr^ 2

$\LARGE{ \underline{ \orange{ \sf{Solution:}}}}$

551 = 1/2×7×height

157.4 cm^2

Volume of cone = 1/3πr^2=height

1/3×22/7×7/7×157.4×1

164.89cm^2

hope it helps........... ⚠️

Answer 2

Step-by-step explanation:

$\huge\fcolorbox{blue}{green}{Given}$

• Area of Canvas = 551 m^2.

• Wastage of 1 m

• 550 - 1 = 550m^2

$\huge\fcolorbox{blue}{green}{Formula Used}$

• Curved surface area of cone = πrl

• l^2 = r^2 + h^2.

$\huge\fcolorbox{blue}{green}{Solution}$

# h = √l^2 - r^2

# h = √25 - 7

# h = 24 cm

# Volume of Cone = 1/3πr^2h

1/3 * 22/7 * 7 * 7 * 24 = 1232m^2