Question

Monica is one year older than twice her sister’s age. The difference of their ages is 8. Find their present ages.

Answer 1

Answer:

let monika be 2x+1

her sister be x

equation

(2x+1) -(2x) =8

solution 2x+1-x= 8

2x-x=8-1

x= 7

Answer 2

The present age of monica and her sister is 15 and 7

Step-by-step explanation:

Let the monica age be x

let the her sister's age be y

A/Q

     $x=2y+1$.....eq(1)

also

     $x-y=8$.......e(2)

  0n substituting the value of x from eq(1) to eq(2) we get

  $=>2y+1-y=8$

 $=>y=7$

subtituting the value of y in eq(2) we get

$=>x-=7=8\\=>x=15$

Hence theier present ages are 15,7