Monika jogs around a square park of side of its 250m. Latika jogs around a
rectangular parkof length 80m and breadth 65m. Who covers a greater distance
and by how much?
Answers
Given -
Monika jogs around a square park of the side of its 250m. Latika jogs around a rectangular park of length 80m and breadth 65m.
To find -
- Who covers a greater distance and by how much?
Solution -
Monika jogs around a square park of the side of its 250m.
- Length of square park = 250 m
According to the formula of the perimeter of the square
→ 4 × side
→ 4 × 250
→ 1000m
Now,
Latika jogs around a rectangular park of length 80m and breadth 65m.
- Length of rectangular park = 80m
- Breadth of rectangular park = 65m
According to the formula of the perimeter of a rectangle
→ 2(l + b)
→ 2(80 + 65)
→ 2 × 145
→ 290m
•°• Monika will cover a greater distance and she will travel 710m more from Latika
________________________________
Answer:
Given :-
- Monika jogs around a square park of its 250 m. Latika jogs around a rectangular park of length 80 m and breadth 65 m.
To Find :-
- How much distance covered and how much.
Formula Used :-
✪ Perimeter of a square = 4 × side ✪
★ Perimeter of a rectangle = 2(L + B) ★
where,
- L = Length
- B = Breadth
Solution :-
First, we have to find the perimeter of a square by Monika,
Given :
- Side = 250 m
According to the question by using the formula we get,
⇒ Perimeter of a square = 4 × side
⇒ Perimeter of a square = 4 × 250 m
➠ Perimeter of a square = 1000 m
Hence, the perimeter of a square is 1000 m .
Now, we have to find the perimeter of a rectangle by Latika,
Given :
- Length = 80 m
- Breadth = 65 m
According to the question by using the formula we get,
↦ Perimeter of a rectangle = 2(L + B)
↦ Perimeter of a rectangle = 2(80 + 65)
↦ Perimeter of a rectangle = 2(145)
↦ Perimeter of a rectangle = 2 × 145
➦ Perimeter of a rectangle = 290 m
Now, we have to find the difference between the distance between the Monika and Latika,
⇒ 1000 - 290
➤ 710 m
∴ Monika is covered greater distance from Latika and she travels 710 m.