Question

Monisha has a garden in the shape of a rhombus.The perimeter of garden is 40m and its diagonals is 16m. She wants to divide it is into two equal parts.Find the area of each part of garden?​

Answer 1

Step-by-step explanation:

a half of the earth, usually as divided into northern and southern halves by the equator, or into western and eastern halves by an imaginary line passing through the poles.

a half of the celestial sphere.

Answer 2

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Monisha has a garden in the shape of a rhombus.The perimeter of garden is 40m and its diagonals is 16m. She wants to divide it is into two equal parts.Find the area of each part of garden?

${\large{\mathbb{\blue{\overline{\underline{\red{\overbrace{\underbrace{\orange{GIVEN}}}}}}}}}}$

PERIMETER=40m

LENGTH OF ONE DIAGONAL=16m

${\large{\mathbb{\blue{\overline{\underline{\red{\overbrace{\underbrace{\orange{SOLUTION}}}}}}}}}}$

As, the garden is in the shape of rhombus,so it has it's all sides equal.

Hence,

$Length \: of \: each \: side= \frac{40}{4} m$

$Length \: of \: each \: side= 10m$

Let the length of the second diagonal be n.

${\blue{a = \frac{ \sqrt{ {m}^{2} + {n}^{2} } }{2} }}$

Where,

a=length of side

m=length of first diagonal

n=length of second diagonal

$———————————————$

$10 = \frac{ \sqrt{ {(16)}^{2} + {(n)}^{2} } }{2}$

$10 \times 2 = \sqrt{ {(16)}^{2} + {(n)}^{2} }$

${(20)}^{2} = 256 + {n}^{2}$

$n = \sqrt{400 - 256}$

$n = 12m$

$———————————————$

Therefore, length of second diagonal is 12m.

$Area \: of \: garden= \frac{(m \times n)}{2}$

$= \frac{(16 \times 12)}{2}$

$= 96 \: {m}^{2}$

$———————————————$

$Area \: of \: one \: part \: of \: the \: garden= \frac{96}{2} {m}^{2}$

$={\green{ 48 {m}^{2} }}$

${\huge{\mathbb{\blue{\overline{\underline{\red{\overbrace{\underbrace{\orange{ANSWER}}}}}}}}}}$

${\huge{\mathcal{\pink{48m²}}}}$

$———————————————$

${\large{\mathcal{\purple{Have \: a \: nice \: day \: ahead}}}}$