monkey of mass 20kg is holding a verticle rope. The rope can stand a maximum tension of 250 N. What is the maximum acceleration with which the monkey can climbs up along the rope (g=10m/s)
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The rope will not break unto 20kg it means it is its tension.
Thus balance condition
is T-mg=ma
25g-20g= 20a (g=10) thus on solving a=50/20= 2.5m/s^ (ans)
So this monkey can have max acceleration of2.5 if he really wants to climb the tree
Let the Monkey be climbing up with an acceleration 'a'.
Tension in string =m(g+a)
=Breaking force
20(g+a)=25×g
a=g4
=104
=2.5m/s2
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Answer:
What is the maximum acceleration with which the monkey can climb up along the rope? (g=10m//s^(2)) . Maximum tension in rope. Equation of motion of monkey. 250-20×10=20×a implies a=2.5m/s2
Explanation:
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