Question

monkey of mass 30kg climbs a rope which can withstand a maximum tension of 360n find the maximum acceleration the rope can tolerate?

Answer 1

hope the accl is 2m/s2 its the correct

Answer 2

We know,

T - mg = ma

here,

T = 360 n

m = 30kg

g = 9.2 m/s²

a = ?

hence,

360 - 30*9.2 = 30a

or, 30a = 360 - 276 = 84

or, a = 84/30 = 2.8

therefore accelaration = 2.8 m/s²