monochromatic light of wavelength 600 NM enters from air into a glass medium of refractive index 1.5 the wavelength of refracted light inside the glass is
Answers
c = Speed of light in air → 3 X 10^8 m/s
W → Wavelength
n → Refractive index of the medium = 1.5
W in air = 6000 A = 6 X 10^-7 metres
λ → Frequency in air = c / W in air = 5 X 10^14 Hz
n = W in air / W in the medium
1.5 = 6000 / W in the medium
W in the medium = 4000 A
Magnitude of frequency depends upon the light producing source hence it remains constant throughout ( 5 X 10^14 Hz) .
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OTHER ANSWERS
Saumya Kanta Swain
Saumya Kanta Swain, former Engineer at Aditya Birla Group (2013-2016)
Answered Sep 21, 2018
When light enters an optically denser medium, it’s velocity reduces while its frequency remains unchanged. Refractive index of a substance wrt vacuum can be equivalently defined as:
Considering air to be equivalent to vacuum
Refractive index of a medium wrt vacuum, n, = λ(in vacuum)/λ(in medium)
or equivalently n = v(in vacuum)/v(in medium)
=> λ(in medium) = λ(in vacuum)/1.5 = 6000/1.5 = 4000
Frequency (ν) does not change with medium. We know the wavelength and speed in air (or vacuum). So,
ν = v(velocity in vacuum)/λ(wavelength in vacuum)
= c/6000Å = 3*10^8/6*10^-7 = 5*10^14
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Satya Parkash Sud
Satya Parkash Sud, M.Sc. Physics & Nuclear Physics, University of Delhi (1962)
Answered Sep 13, 2017 · Author has 2.2k answers and 4.1m answer views
Wavelength of light in air = 6000A°= 6000A°×10^-8 cm/A° = 6× 10^-5 cm
The velocity of light in air= 3×10^10 cm/s
Frequency v of light in air (velocity of light in air in cm/s) ÷ wave length of light in cm= ( 3×10^10 cm/s)/6×10^-5 cm= 5×10^14 Hz.
On entering the medium of refractive index n= 1.5 from air, the velocity of light decreases to c'= c/n= 3×10^10 cm per sec./ 1.5 = 2×10^10 cm/s.
The frequency of light does not change on refraction. So frequency of light in the medium= 5×10^14 Hz.
To keep the frequency unchanged, the wavelength of light in the medium also decreases by the same factor as the decrease in the velocity of light. So altered wavelength of light in the medium= 6000A°/1.5 = 4000A° .
So frequency of light in the medium= 5×10^14 Hz.
Wavelength of light in the medium= 4000A° .
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