Monochromatic radiation emitted when electron on hydrogen atom jumps from first excited to the ground state irradiates a photosensitive material. The stopping potential is measured to be 3.57 V. The threshold frequency of the material is
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Answer 》 Monochromatic radiation emitted when electron on hydrogen atom jumps from first excited to the ground state irradiates a photosensitive material. The stopping potential is measured to be 3.57 V. The threshold frequency of the material is 1.6 × 10^5 Hz
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Energy realised from emission of electron
E= (-3.4) - (-13.6)= 10.2 ev
From Photo electric equation work function
ø = E- ev = hv
v = E - ev / h
(10.2) - (3.57)e / 6.67 × 10 ^34
v = 6.63 × 1.6 × 10 ^19 / 6.67 × 10 ^34
= 1.6 × 10^5 Hz answer
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Answer:
For hydrogen atom the energy in nth state is
En=
First excited state means second normal state i.e
ground state is n=1 so the energy of emitted photon will be
E= -(E1-E2)
−13.6eV(−1+1/4)=10.2 ev
Stopping potential
on using Einstein equation, eV =E−W, W is work function
so W=(10.2−3.57)eV=6.63eV=6.63×1.6×10^-19joule
=1.0608×10^-18 Joule
the threshold frequency , f=W/h......(1)
h is Planck's constant h=6.62×10^-34Js
putting these values in equation-1 , we get
f=1.6×10^15Hz