Monthly income of ram and Rahim are in the ratio 5:7. Their monthly expense are in the ratio of 7:1. If each of them saves ₹60 per month, then compute their monthly income
Answers
Answer:
\huge\sf{Answer:}Answer:
\underline{\tt Given :}
Given:
➳ Monthly incomes of two persons Ram and Rahim are in the ratio 5:7 and their monthly expenditures are in the ratio 7:11. If each of them saves 60 per month.
\underline{\tt Find :}
Find:
➳ Find their monthly income.
\underline{\tt Calculations :}
Calculations:
\underline{\tt According \ to \ the \ given \ question, \ as \ follows:}
According to the given question, as follows:
➳ Monthly income of Ram and Ramin are given in ratios as follows: (5:7).
➳ Let us assume the monthly income of Ram and Ramin as follows: (5x and 7x).
➳ The money expenditures of Ram and Ramin are given in ratios as follows: (7:11).
➳ Let us assume the money expenditures of Ram and Ramin as follows: (7y and 11y).
\underline{\tt Using \ the \ above \ cases \ according \ to \ question, \ as \ follows:}
Using the above cases according to question, as follows:
\sf\rightarrow 5x - 7y = 60 - Equation(1) →5x−7y=60−Equation(1)
\sf\rightarrow 7x - 11y = 60 - Equation(2) →7x−11y=60−Equation(2)
\sf\underline{\tt Adding \ values \ to \ the \ equation(1) \ as \ follows:}
Adding values to the equation(1) as follows:
\sf\rightarrow 5x - 7y = 60 →5x−7y=60
\sf\rightarrow 5x = 60 + 7y →5x=60+7y
\sf\rightarrow \dfrac{60 + 7y}{5} \ Equation(3) →
5
60+7y
Equation(3)
\sf\underline{\tt Adding \ values \ to \ the \ equation(2) \ as \ follows:}
Adding values to the equation(2) as follows:
\sf\rightarrow 7 \ ( \dfrac{60 + 7y}{5} ) \ - 11y = 60 →7 (
5
60+7y
) −11y=60
\sf\rightarrow \dfrac{420 + 49y}{5} \ - 11y = 60 →
5
420+49y
−11y=60
\sf\rightarrow 420 + 49y - 55y = 300 →420+49y−55y=300
\sf\rightarrow 420 - 6y = 300 →420−6y=300
\sf\rightarrow -6y = 300 - 420 →−6y=300−420
\sf\rightarrow -6y = - 120 →−6y=−120
\sf\rightarrow y = 20 →y=20
\underline{\tt Adding \ values \ to \ 'y' \ in \ equation(3) \ as \ follows:}
Adding values to
′
y
′
in equation(3) as follows:
\sf\rightarrow x = \dfrac{60 + 7 \times 20}{45} →x=
45
60+7×20
\sf\rightarrow x = \dfrac{60 + 140}{5} →x=
5
60+140
\sf\rightarrow x = \dfrac{200}{5} →x=
5
200
\sf\rightarrow x = 40 →x=40
Therefore, their montly incomes are as follows:
➳ 5x = (5 × 40) = 400 is the monthly income of Ram.
➳ 7x = (7 × 40) = 280 is the monthly income of Rahim.