Math, asked by thelegend86, 1 year ago

Monthly incomes of Mohan and Sohan are in the ratio

3 : 2 and their monthly expenditures are in the ratio 5 : 3. If each saves Rs. 6000

per month then the difference in their incomes is

(A) Rs. 12,000 (B) Rs. 10,000

(C) Rs. 8,000 (D) Rs. 6,000​

Answers

Answered by anonlocalthito
4

Answer:

A) 12000

Step-by-step explanation:

Let 3x be thge income of Mohan and 2x be the income of Rohan.

And let the expenditureof Mohan be 5y and that of Rohan be 3y.

According to question they both save Rs 6000. So,

3x-5y=6000...i

2x-3y=6000...ii

Multiplying equation i by 3 and ii by 5 and subtracting ii from i,

9x-15y=18000

10x-15y=30000

-     +       -

_____________

-x = -12000

x=12000

Hence,

Mohan's income=3x=3*12000= 36000

Rohan's income=2x = 2*12000= 24000

Now,

The difference between their income= 36000-24000

                                                                 =12000

Answered by aksharrao1423
0

Answer:

Answer:

A) 12000

Step-by-step explanation:

Let 3x be thge income of Mohan and 2x be the income of Rohan.

And let the expenditureof Mohan be 5y and that of Rohan be 3y.

According to question they both save Rs 6000. So,

3x-5y=6000...i

2x-3y=6000...ii

Multiplying equation i by 3 and ii by 5 and subtracting ii from i,

9x-15y=18000

10x-15y=30000

-     +       -

_____________

-x = -12000

x=12000

Hence,

Mohan's income=3x=3*12000= 36000

Rohan's income=2x = 2*12000= 24000

Now,

The difference between their income= 36000-24000

                                                                =12000

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