Math, asked by rathanveer, 6 months ago

Monthly salaries of 1000 workorels
have a normal distribution with
mean of Rs 575 and standard deviation of Rs75
Find number of workers having
salaries between Rs 500 and Rs 625
Also find minimum salary of highest
paid 200 workers?​

Answers

Answered by amitnrw
0

Given :  Monthly salaries of 1000 workers  have a normal distribution with

mean of Rs 575 and standard deviation of Rs 75

To find : number of workers having  salaries between Rs 500 and Rs 625

minimum salary of highest  paid 200 workers

Solution:

Mean Salary = Rs 575

SD = Rs 75

between Rs 500 and Rs 625

Z score = (Value - Mean)/SD

= ( 500 - 575 )/75

= - 1

=> 15.87 %  workers having salary below this

(625 - 575)/75

= 50/75

= 2/3

= 0.667

=> 74.8  %  workers having salary below this

salaries between Rs 500 and Rs 625 = 74.8  %   - 15.87 % = 61 %

= 610

610 workers have salaries between Rs 500 and Rs 625

minimum salary of highest  paid 200 workers

200 workers = 20 %

=> 80 % workers below  salary of  minimum salary of highest

paid 200 workers

=> z = 0.841

0.841  = ( Value -  575)/75

=> Value = 638

minimum salary of highest  paid 200 workers  = Rs 638

Learn More:

Assume that adults have iq scores that are normally distributed with ...

https://brainly.in/question/11133397

The value of the cumulative standardized normal distribution at z is ...

https://brainly.in/question/11376268

Attachments:
Similar questions