Question

Monu 's father is 26 years younger than monu's grandfather and 29 years older than monu. The sum of the ages of all three is 135 years.What is the age of each one of tham

Answer 1

Answer:

+x+Let, Baichung's age = x years His

father's age=x+29 years    His

grandfather' age=x+29+26 years Sum of their ages=135 years x+x+29+x+29+26=135 3x+84=1353x=135-84 3x=51 x=51/3 x=17 Therefore,Baichung's age= 17years His Father's age=17+29=46 years His grandfather's age=17+29+26=72 years.(to check add all the three age(it will be 135 years)). hope u are able to understand...

substitute

MONU FROM BAICHUNG

Answer 2

Answer:

Let the age of Monu = x years

Given that Monu's father is 29 years older than Monu.

Therefore

Monu's father age = x + 29 years

Also given that Monu's grandfather is 26 years older than Monu's father

Therefore

Monu' grandfather age = Monu's father age + 26 years

                                        =  x + 29 + 26

                                        =  x + 55 years

Also given that the sum of their ages = 135

Therefore

x + x + 29 + x + 55 = 135

3x + 84 = 135

3x = 135 - 84

x = 51/3

x = 17 years

The age of Monu = x years = 17 years

The age of Monu's father = x + 29 = 46 years

The age of Monu's grandfather = x + 55 = 72 years.

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