Math, asked by lek3yCmapumekursha, 1 year ago

Monu's father is 26 years younger than Monu's grandfather and 29 years older than Monu.The sum of the ages ofof all the three is 135 years.What is the age of each one of them?

Answers

Answered by yakumoreyucurry
597
Let Father's age be x
Let Monu's age be x-29
Let Grandfather's age be x+26
A/Q (x-29)+x+(x+26) = 135
3x-3 = 135
3x = 138
x = 46
Father's age = 46 years
Monu's age = x-29 = 46-29 = 17 years
Grandfather's age = x+26 = 46+26 = 72 years

yakumoreyucurry: Please mark this answer as Brainliest, for I really need them.
Answered by Anonymous
218
Solutions :-


Let the Father's age be x
Monu's age = x - 29
Grandfather's age = x + 26

The sum of the ages of all three = 135


A/q

=> x + x - 29 + x + 26 = 135
=> 3x - 29 + 26 = 135
=> 3x - 3 = 135
=> 3x = 135 + 3
=> 3x = 138
=> x = 138/3 = 46



Hence,
Father's age = x = 46 years
Monu's age = x - 29 = 46 - 29 = 17 years
Grandfather's age = x + 26 = 46 + 26 = 72 years
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