Monu's father is 26 years younger than Monu's grandfather and 29 years older than Monu.The sum of the ages ofof all the three is 135 years.What is the age of each one of them?
Answers
Answered by
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Let Father's age be x
Let Monu's age be x-29
Let Grandfather's age be x+26
A/Q (x-29)+x+(x+26) = 135
3x-3 = 135
3x = 138
x = 46
Father's age = 46 years
Monu's age = x-29 = 46-29 = 17 years
Grandfather's age = x+26 = 46+26 = 72 years
Let Monu's age be x-29
Let Grandfather's age be x+26
A/Q (x-29)+x+(x+26) = 135
3x-3 = 135
3x = 138
x = 46
Father's age = 46 years
Monu's age = x-29 = 46-29 = 17 years
Grandfather's age = x+26 = 46+26 = 72 years
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Solutions :-
Let the Father's age be x
Monu's age = x - 29
Grandfather's age = x + 26
The sum of the ages of all three = 135
A/q
=> x + x - 29 + x + 26 = 135
=> 3x - 29 + 26 = 135
=> 3x - 3 = 135
=> 3x = 135 + 3
=> 3x = 138
=> x = 138/3 = 46
Hence,
Father's age = x = 46 years
Monu's age = x - 29 = 46 - 29 = 17 years
Grandfather's age = x + 26 = 46 + 26 = 72 years
Let the Father's age be x
Monu's age = x - 29
Grandfather's age = x + 26
The sum of the ages of all three = 135
A/q
=> x + x - 29 + x + 26 = 135
=> 3x - 29 + 26 = 135
=> 3x - 3 = 135
=> 3x = 135 + 3
=> 3x = 138
=> x = 138/3 = 46
Hence,
Father's age = x = 46 years
Monu's age = x - 29 = 46 - 29 = 17 years
Grandfather's age = x + 26 = 46 + 26 = 72 years
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