Question

Monu's father is 4 times as old as he is. After 20 years, his age will be twice that of Monu's.
Find their present ages.​

Answer 1

Answer:

Let x be the age of his son now, then the age of the father is 4x.

In 20 years,

The son's age = x + 20

The father's age = 4x + 20

As in 20 years the father will be twice as old as his son, we can set up an equation:

4x + 20 = 2(x + 20)

Solving the equation for x, we have

4x + 20 = 2x + 40

2x = 20

x = 10

So the age of his son now is 10, and the age of the the father now is 40.

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Answer 2

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