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minimum no of attempt -3
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Minimum 2 iterations.
- Make 3 sets of 3 balls.
- Compare any of the two sets. If both weighs the same, it means the last set has the heavier ball. Weigh 2 balls of that set, if both ball weighs the same then last ball of that set is heavier. Else the heavier ball is the heavier in the last set.
Lets go to step1 again.
- If the first 2 sets are unequal, extract the heavier set, weigh the 2 balls out of it, if they are equal then the third one is heavier, else the heavier ball is heavier.
So, 2 iterations are minimum.
hope it helps....
- Make 3 sets of 3 balls.
- Compare any of the two sets. If both weighs the same, it means the last set has the heavier ball. Weigh 2 balls of that set, if both ball weighs the same then last ball of that set is heavier. Else the heavier ball is the heavier in the last set.
Lets go to step1 again.
- If the first 2 sets are unequal, extract the heavier set, weigh the 2 balls out of it, if they are equal then the third one is heavier, else the heavier ball is heavier.
So, 2 iterations are minimum.
hope it helps....
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