Question

more than 216 km/h)
340 m/s (which is 1224 km/h)
Sample Problem 5. A scooter moving at a speed of 10 m/s is stopped by applying brakes which produce
a uniform acceleration of, -0.5 m/s. How much distance will be covered by the scooter before it stops ?
Solution. Here, Initial speed, 10 m/s​

Answer 1

Answer:

100 m

Explanation:

As per the provided information in the given question, we have :

• Initial velocity (u) = 10 m/s
• Final velocity (v) = 0 m/s (As it stops)
• Acceleration (a) = -0.5 m/s²

We are asked to calculate the distance that will be covered by the scooter before it stops.

By using the third equation of motion,

$\longmapsto\bf{ v^2 - u^2 = 2as}$

• v denotes final velocity
• u denotes initial velocity
• a denotes acceleration
• t denotes time

$\longmapsto\rm{ (0)^2 - (10)^2 = 2(-0.5)(s)}$

$\longmapsto\rm{ 0 -100 =-1s}$

$\longmapsto\rm{ -100 =-1s}$

$\longmapsto\bf{ 100 \; m= s}$

Therefore, distance travelled by the scooter before it stops is 100 m.

Learn More!!

Equations of motion :

$\boxed{ \begin{array}{cc} \pmb{\sf{ \quad \: v = u + at \quad}} \\ \\ \pmb{\sf{ \quad \: s= ut + \cfrac{1}{2}a{t}^{2} \quad \: } } \\ \\ \pmb{\sf{ \quad \: {v}^{2} - {u}^{2} = 2as \quad \:}}\end{array}}$

• v denotes final velocity
• u denotes initial velocity
• a denotes acceleration
• t denotes time
• s denotes distance