Question

More Trigonometry tan given, find sin cos expression ​

Answer 1

Answer:

Step-by-step explanation:

5 tan∅ = 4

=> tan∅ = 4/5

=>P/B = 4/5

=> P=4 , B = 5

=> H=$\sqrt{P^{2}+B^2 }$

=> H = $\sqrt{16+25}$

=> H = $\sqrt{41}$

put it in the value of sin∅ and cos∅

Answer 2

Step-by-step explanation:

Easy method of solving this is

$\\ = \frac{5 \sin(x) - 3 \cos(x) }{ 5 \sin(x) + 2 \cos(x) }$

Now Multiply numerator and denominator by 1/cos(x)

$\\ = \frac{5 \tan(x) - 3}{5 \tan(x) + 2 }$

Now use the value of tanx

$\\ = \frac{1}{6}$