❤ Mosquito = Elephant ❤
Mathematical fallacy,
Proof that an elephant and a mosquito have the same mass.
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Answered by
5
Hi.... ✌✌
Here's your answer.... ✔✔
❤❤❤Let a = mass of elephant in kg
Let x = mass of mosquito in kg
Let y = their combined mass in kg
Then:
\begin{align}&a+x=y\\&a=y-x\\&a-y=-x\end{align}
multiplying the two latter equations:
a^2-ay=x^2-xy
adding \left(\frac{y}{2}\right)^2 to both sides:
a^2-ay+\left(\frac{y}{2}\right)^2=x^2-xy+(\frac{y}{2})^2
which can be rewritten:
\left(a-\frac{y}{2}\right)^2=\left(x-\frac{y}{2}\right)^2
from which derives:
a-\frac{y}{2}=x-\frac{y}{2}
and finally:
a=x
that is, mass of elephant = mass of mosquito.❤❤❤
Hope it helps you... ✌✌
Here's your answer.... ✔✔
❤❤❤Let a = mass of elephant in kg
Let x = mass of mosquito in kg
Let y = their combined mass in kg
Then:
\begin{align}&a+x=y\\&a=y-x\\&a-y=-x\end{align}
multiplying the two latter equations:
a^2-ay=x^2-xy
adding \left(\frac{y}{2}\right)^2 to both sides:
a^2-ay+\left(\frac{y}{2}\right)^2=x^2-xy+(\frac{y}{2})^2
which can be rewritten:
\left(a-\frac{y}{2}\right)^2=\left(x-\frac{y}{2}\right)^2
from which derives:
a-\frac{y}{2}=x-\frac{y}{2}
and finally:
a=x
that is, mass of elephant = mass of mosquito.❤❤❤
Hope it helps you... ✌✌
Answered by
6
there's your answer dear
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