Question

mother age 25 year older than her son . Find son's age if after 8 years ratio son's age to mother's age will be 4/9​

Answer 1

Given data : Mother age is 25 year older than her son and after 8 years ratio son's age to mother's age will be 4/9.

To find : Age if the son ?

Solution : Let, age of son be ‘ x ’ years

Hence, age of mother is ‘ x + 25 ’ years.

Now, according to given,

Age of son and age if mother after 8 year will be :

⟹ Son age after 8 year

= {x + 8} years

Similarly,

⟹ Mother age after 8 year

= {x + 25 + 8} years

⟹ Mother age after 8 year

= {x + 33} years

Now, according to given, after 8 years the ratio son's age to mother's age will be 4/9, hence :

⟹ {son age}/{mother age} = 4/9

⟹ {x + 8}/{x+33} = 4/9

⟹ 9*{x + 8} = 4*{x+33}

⟹ 9x + 72 = 4x + 132

⟹ 9x - 4x = 132 - 72

⟹ 5x = 60

⟹ x = 60/5

⟹ x = 12 years

Answer : Hence, age of son is 12 years.

{ More :

⟹ Age of mother = x + 25

⟹ Age of mother = 12 + 25

⟹ Age of mother = 37 years }

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Answer 2

Answer:

Let’s consider the present age of the son be x years.

Then, the age of the mother = (x + 25) years

Now, after 8 years

Age of son = (x + 8) years

Age of mother = (x + 25+ 8) years = (x + 33) years

From the given information, we have

x+8/x+33=4/9

On cross-multiplying,

9(x + 8) = 4(x + 33)

9x + 72 = 4x + 132

9x – 4x = 132 – 72

5x = 60

⇒ x = 12

Thus, the present age of the son is 12 years.