Question

mother bought 3/4 kg flour. she used 1/3 of it to make a cake. she put the remainder equally in 4 packets. how many grams of flour did each packet contain.​

Answer 1

Step-by-step explanation:

total weight of flour=3/4kg

consumption of flour=1/3

weight of remaining flour=3/4-1/3

=9-4/12

=5/12kg

now weight of grams contain in each packet=1/4÷5/12

=3/5kg

so weight of flour in gram

3/5*1000

600g

hence the weight of flour contain 600g in each packet

I hope that you must be satisfied for any mistake please forgive me and mark me brainlist

Answer 2

Given,

Total flour bought = 3/4 kg,

Used to make cake = 1/3 of it,

The remaining was put in 4 packets equally.

To find,

Quantity in grams that each packet contains.

Solution,

It is given that out of a total of $\frac{3}{4}$ kg bought flour, $\frac{1}{3}$ of it, was used to make a cake.

It means, the flour used to make the cake was

$\frac{1}{3}$ of $\frac{3}{4} kg$

$=\frac{1}{3} (\frac{3}{4} )=\frac{1}{4} kg$

Now, the remaining flour will be

$\frac{3}{4} -\frac{1}{4} =\frac{2}{4} =\frac{1}{2} kg$

In grams, $\frac{1}{2} kg$ will be,

$\frac{1}{2} \times 1000\hspace{3}grams$

= 500 grams.

As it is given that the remaining flour that is, 500 g, was put equally in 4 packets.

Let x grams be the flour put in 1 packet. So,

4x = 500

⇒ $x =\frac{500}{4}$

⇒ x = 125 g.

Therefore, each packet contains 125 grams of flour.