Question

Mother
I prove that sinzo + cos2 o=1 1​

Answer 1

Answer:

Sory I dont know what to do that sum

Sorry friend [●●]

Answer 2

Let a, b, c be the lengths of right angled triangle.

By definition,

$sin \: \theta = \frac{opp}{hyp} = \frac{b}{c}$

$cos \: \theta = \frac{adj}{hyp} = \frac{a}{c}$

${sin}^{2} \theta + {cos}^{2} \theta = \frac{ {b}^{2} }{ {c}^{2} } + \frac{ {a}^{2} }{ {c}^{2} } \\ \\ = \frac{ {a}^{2} + {b}^{2} }{ {c}^{2} }$

From Pythagoras theorem,

c² = a² + b²

$\therefore \frac{ {a}^{2} + {b}^{2} }{ {c}^{2} } = 1$

${sin}^{2} \theta + {cos}^{2} \theta = 1$

Hence proved.

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