Question

Mother is 25 year older than her son.Find son's age if after 8 years ratio of son's age to mother's age will be 4:9​

Answer 1

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Let present age of son be X years.

and mother be = (X+25) yrs.

After 8 years age of son= (X+8) yrs.

and mother's = (X+25+8) = (X+33) yrs.

Now ;

⇒ X+ 8 / X + 33 = 4/9

⇒ 9 ( X + 8 ) = 4 ( X + 33 )

⇒ 9X + 72 = 4X + 132

⇒ 9X - 4X = 132 - 72

⇒ 5X = 60

∴ X = 60/5

⇒∴ X = 12 yrs.

∴ Present age of son = X = 12 Years.

And mother = X + 25 = 12 + 25 = 37 years.

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Answer 2

Step-by-step explanation:

Heya !!

Let present age of son be X years.

Age of mother = ( X + 25 ) years.

After 8 years age of son= ( X + 8 ) years.

After 8 years age of mother = ( X + 25 + 8 ) = ( X + 33 ) years.

According to the question,

X+ 8 / X + 33 = 4/9

9 ( X + 8 ) = 4 ( X + 33 )

9X + 72 = 4X + 132

9X - 4X = 132 - 72

5X = 60

X = 60/5

X = 12 years.

Present age of son = X = 12 Years.

And,

Present age of mother = X + 25 = 12 + 25 = 37 years.

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